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Calibration Fluke 5720A with Fluke 5790A

Dear all,

I am new with this program!

I try to make this procedure but I got big problem:

How to put external guard on Fluke 5790A when it is standard?

 

Best regards!

15 comments

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david morgan

IEEE    [@5790]EXTGUARD ON

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david morgan

If you're not using IEEE statements, use the ACMS FSC

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Srdjan Calija

Thanks!

This is OK!!!

IEEE    [@5790]EXTGUARD ON

but when come this line external guard become OFF

1.023  5790   2.2   2.000000mV     0.305%        10H            I2       2W

I try to put in all mods G but this is not for this standard?

 

Any comments?

Thanks in advance!!!

 

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david morgan

Mixing IEEE & instrument-specific FSCs is usually not efficient & can be confusing. I see from your code you are using the 5790 FSC, so I think it best for you to use the ACMS FSC for "special" configurations like Guarding.

 

In Editor, select FSC Help from the Help menu, type "ACMS" in the search box & read up on how to use that functionality for the 5790.

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Srdjan Calija

Thanks!

 

I find in ACMS when you put G in MOD2 it is working external guard.

I find here!!!  - 5080A_Calibration_313_MB (put this in google)

Sorry for bad English.

Best regards!!!

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Srdjan Calija

Dear all,

 

In this line for calibration 5720A with 5790A:

1.022  5790   2.2   2.000000mV     0.305%        10H            I1       2W

what is 0.305% (tolerance)???

Is this Uncertainty of 5790A or ???

 

Best regards!

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William Green

The 0.305% is the tolerance of the UUT. Not the Fluke 5790A. You can verify this in the UUT specifications. The UUT 1 yr specs for the Fluke 5720A Series II is 300ppm + 5 uV. Should be 0.03% + 0.005U. Doesn't look right, but I'd need to see the whole program. 

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Srdjan Calija

Dear Bill,

At first thanks!

 

I find this in some old procedure!

For my 5720A specification for this calibrator for range 2.2mV for 10-20 Hz is 240ppm + 4uV!

 

For 2mV I calculated 2240ppm or 0.224% is that mean that this line must be like this:

 

 1.023  5790   2.2   2.000000mV     0.224%        10H            I1       2W

 

 

Best regards!

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Dale Chaudiere

The specification should be entered in the TOLERANCE field exactly as published, so that it can be easily audited.

240ppm = 240P%

4uV = 0.004000U

  1.001  TOL      240P% 0.004000U

  1.002  5790  2.2  2.000000mV      TOL     10H         I1       2W

#! WARNING:   Test Tol 4.48e--6, Sys Fol 4.7e-006 V, TUR 0.9532 (< 4.00).

THE 5720A IS MORE ACCURATE THEN THE 5790A AT 2 mV, 10 Hz!!!   How can you justify using the 5790A absolute accuracy for this test?

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Srdjan Calija

Dear Dale,

 

Yes I know that TUR is lower than 1!

For this range this is some kind of verification - not calibration.

Thanks for this function - TOL.

 

I calculate like this for 2mV 10Hz:

 ( ( (240/10^6)*2*10^-3 + 4*10^-6 ) / 2*10^-3 )*10^6

 

and result is 2240ppm or 0.224%

 

and I think that this line now is corect

 

1.023  5790   2.2   2.000000mV     0.224%        10H            I1       2W

 

I do not have enough experience with metcal - what do you think about this line?

 

Thanks for help!

 

Best regards!

 

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Dale Chaudiere

I do not understand all the extra math you are doing.  Again, enter the 5720A published specification as written (ppm of output + floor).  The only thing to be aware of is that the floor needs to be entered in units of the NOMINAL field (e.g. mV).  That is all there is to it.  MET/CAL will automatically perform the math.

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Srdjan Calija

Dear Dale,

 

( ( (240/10^6)*2*10^-3 + 4*10^-6 ) / 2*10^-3 )*10^6

 

This is 240 ppm of output

(240/10^6)*2*10^-3  = 4.80E-07

This is floor

4*10^-6 = 4.00E-06

 

4.80E-07 + 4.00E-06 =4.48E-06

When I divide this with

/ 2*10^-3 = 2.24E-03

I got now relative value and multiple with 10E6 (10^6)

Then i got value in ppm

2240ppm

 

Tanks for everything!

Best regards!

 

 

 

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Srdjan Calija

Dear All

I finaly got it

 

1.022  5790   2.2   2.000000mV     0.305%        10H            I1       2W

 

This program be for 5700 for 99% and 90 days then is 550ppm + 5 uV

 

When calculate with formulas up you got:

3050ppm or 0.305%

 

Best regards and thaks for help!

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Dale Chaudiere

Again, why are you pre-computing the tolerance in percent?  Why can't you just enter the published specification in the TOLERANCE field and let MET/CAL perform the math as it was designed to do?

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Srdjan Calija

Dear Dale,

 

I make changes of some old program and there is problem solved like this.

It is easier for me to change some number than to change all program.

You are right and for new program I am gona use your example it is beter and you can see what you use in line TOL.

 

Thank you very much!

 

 

Best regards!

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